/INTER/SUB

Block Format Keyword Defines a sub-interface. A sub-interface is a portion of an existing interface and is defined in order to output the forces applied by nodes of a specified node group on the segments of a specified surface (refer to Time Histories output for interfaces).

Format

(1) (2) (3) (4) (5) (6) (7) (8) (9) (10)
/INTER/SUB/sub_inter_ID
sub_inter_title
inter_ID Master_ID1 Slave_ID Master_ID2            

Definitions

Field Contents SI Unit Example
sub_inter_ID Sub interface identifier.

(Integer, maximum 10 digits)

  
sub_inter_title Sub interface title.

(Character, maximum 100 characters)

  
inter_ID Interface identifier for the main interface which contains the sub interface.

(Integer)

  
Master_ID1 Master identifier.
= surf_IDm
If inter_ID is TYPE7, TYPE10, TYPE19, or TYPE24
= line_IDm
If inter_ID is TYPE11
= surf_ID
If inter_ID is TYPE25
(Integer)		  
Slave_ID Slave identifier.
= grnd_IDs
If inter_ID is TYPE7, TYPE10, TYPE24, or TYPE25
= line_IDm
If inter_ID is TYPE11
= surf_IDs
If inter_ID is TYPE19 5
(Integer)
  
Master_ID2 Second master surface identifier.
= surf_ID
If inter_ID is TYPE25 6
 

Comments

  1. Only interface TYPE7, TYPE10, TYPE11, TYPE19, TYPE24 and TYPE25 are available for defining sub-interfaces.
  2. A hierarchy of sub-interfaces is not permitted.
  3. An interface and a sub-interface cannot have the same identifier.
  4. For sub-interfaces of TYPE7 TYPE10, TYPE11, TYPE19 and TYPE24:

    All segments of the specified master surface or master line in the sub interface should belong to the master surface or master line of the interface.

    All segments of the specified slave surface or slave line in the sub interface should belong to the slave surface or slave line of the interface.

  5. For sub-interfaces of a TYPE19 interface, if Slave_ID = 0, then the sub-interface is symmetric and Master_ID is also used as slave surface.

    clip0038
    Figure 1.
  6. For sub-interfaces of a TYPE25 interface:

    If Slave_ID ≠ 0, the forces applied by the slave node group onto both master surfaces are considered.

    If Master_ID2 ≠ 0, the forces applied by Master_ID1 onto Master_ID2 and vice versa are calculated.